A loop in a linked list is a situation where a node in the list points to a previous node, causing the list to have a cycle. In other words, a loop occurs when there is at least one node in the list that can be reached by following a chain of next
pointers starting from another node. Loops can cause problems in linked lists because they can create infinite loops when traversing the list, or they can cause algorithms that operate on linked lists to fail. Detecting and removing loops in linked lists is an important task in computer science and is often used in programming interview questions.
class ListNode(var value: Int) {
var next: ListNode? = null
}
class ListNode(var value: Int)
– This is a simple class to define the ListNode
data structure for our linked list. It has a value field to store the integer value of the node, and a next field to point to the next node in the list.
fun detectAndRemoveLoop(head: ListNode?) {
// Step 1: Detect the loop
var slow = head
var fast = head
var loopDetected = false
fun detectAndRemoveLoop(head: ListNode?)
– This is the main function that detects and removes a loop from a linked list. It takes the head of the linked list as input.
var slow = head
– We start by initializing two pointers – slow
and fast
– both pointing to the head of the linked list.
while (fast?.next != null) {
slow = slow?.next
fast = fast.next?.next
if (slow == fast) {
loopDetected = true
break
}
}
while (fast?.next != null)
– We then use the “slow and fast” pointer technique to detect the presence of a loop in the linked list. In each iteration of the loop, we move slow
one node at a time and fast
two nodes at a time. If there is a loop, the fast
pointer will eventually catch up to the slow
pointer.
if (slow == fast) {
loopDetected = true
break
}
}
if (slow == fast)
– If there is a loop, we set the loopDetected
flag to true and break out of the loop.
// Step 2: Find the start of the loop
if (loopDetected) {
var p1 = head
var p2 = slow
while (p1 != p2) {
p1 = p1?.next
p2 = p2?.next
}
val startOfLoop = p1
// Step 3: Remove the loop
var prev = startOfLoop
var current = startOfLoop!!.next
while (current != null && current != startOfLoop) {
prev = current
current = current.next
}
prev!!.next = null
}
if (loopDetected)
– If a loop was detected, we move one pointer (p1
) to the beginning of the linked list and keep the other pointer (p2
) at the point where the two pointers (slow
and fast
) met. We then move both pointers one node at a time until they meet again. The node at which they meet is the start of the loop.
val startOfLoop = p1
– We store the start of the loop in a variable called startOfLoop
.
var prev = startOfLoop
and var current = startOfLoop.next
– We initialize two pointers – prev
and current
– to the node just after the start of the loop.
while (current != startOfLoop)
– We then move both pointers one node at a time until current
points to the node just before the start of the loop.
prev.next = null
– Finally, we set the next
field of the node just before the start of the loop to null
, effectively removing the loop from the linked list.
class Node(var data: Int) {
var next: Node? = null
}
fun findMiddleElement(head: Node?): Int? {
var slowPtr = head
var fastPtr = head
while (fastPtr != null && fastPtr.next != null) {
slowPtr = slowPtr?.next
fastPtr = fastPtr.next?.next
}
return slowPtr?.data
}
fun main() {
// create a linked list
val head = Node(1)
head.next = Node(2)
head.next?.next = Node(3)
head.next?.next?.next = Node(4)
head.next?.next?.next?.next = Node(5)
// find the middle element
val middleElement = findMiddleElement(head)
// print the middle element
if (middleElement != null) {
println("The middle element is $middleElement")
} else {
println("The linked list is empty")
}
}
In this example, we create a linked list with a loop by setting the next
field of the last node to point to the second node in the list. We then call the detectAndRemoveLoop()
function to remove the loop from the linked list. Finally, we print the linked list to verify that the loop has been removed.