To count the number of bits to be flipped to convert A to B using bit manipulation, you can perform the following steps:
- XOR A and B to get a number C that has a 1 in each bit position where A and B differ and a 0 in each bit position where they are the same.
- Count the number of 1’s in C by performing a bit-count operation. There are various ways to do this, but one common method is to use a lookup table that has the number of set bits for each possible 8-bit value, and then combine the counts for each 8-bit chunk of C using bitwise operations.
- The resulting count is the number of bits that need to be flipped to convert A to B.
fun countBitsToFlip(a: Int, b: Int): Int {
var c = a xor b
var count = 0
while (c != 0) {
count += c and 1
c = c shr 1
}
return count
}
fun main() {
val a = 10 // 1010 in binary
val b = 15 // 1111 in binary
val bitsToFlip = countBitsToFlip(a, b)
println("To convert $a to $b, we need to flip $bitsToFlip bits.")
}
In this implementation, we define a function called countBitsToFlip
that takes two integers a
and b
as input and returns the number of bits that need to be flipped to convert a
to b
.
The function first computes the bitwise XOR of a
and b
to get a number c
that has a 1 in each bit position where a
and b
differ and a 0 in each bit position where they are the same.
The function then initializes a counter variable count
to 0 and enters a loop that continues as long as c
is non-zero. In each iteration of the loop, the function checks whether the least significant bit of c
is 1 by performing a bitwise AND with the value 1. If the result is 1, the function increments count
. The function then shifts c
one bit to the right using the shr
operator to check the next bit.
After the loop completes, the function returns the value of count
, which is the number of bits that need to be flipped to convert a
to b
.
Finally, we test the function by calling it with two example inputs and printing the result. The output should be “To convert 10 to 15, we need to flip 2 bits.”